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sriind ca x= 23 si y+z= 41,calculati: 4y+4z+5x. URGENT va rog (dau coronita)


Răspuns :

4x4x41+5x23=
=16x41+115=
=82+115=
=197
[tex]x=23 \\ y+z=41 \\ 4y+4z+5x=4(y+z)+5 x=4 \cdot 41+5 \cdot 23=164+115=279 \\ \boxed{ 4y+4z+5x=279}[/tex]