La prima poza iti iese din teorema lui Thales ca [tex] \frac{5}{6} = \frac{x}{x+0,9} \ \textless \ =\ \textgreater \ 6x=5x+5*0,9 \ \textless \ =\ \textgreater \ x=5* \frac{9}{10} = \frac{9}{2} = 4,5[/tex]
Cu aceasi teorema rezolvi poza a 2-a si iti va iesi ca [tex] \frac{x}{x-4,2} = \frac{6,2}{3,4} \ \textless \ =\ \textgreater \ \frac{x}{x-4,2}= \frac{62}{34} \ \textless \ =\ \textgreater \ 34x=62x-62* \frac{42}{10} \ \textless \ =\ \textgreater \ [/tex][tex]28x=260,4 \ \textless \ =\ \textgreater \ x=9,3[/tex]
