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se da
abcd-romb
ac-24 cm(diagonala)
bd-10 cm(diagonala)
perimetrul rombului?


Răspuns :

[tex] d_{1}^2 + d_{2}^2=2( a^{2} + b^{2} ) [/tex]
[tex]24^2+10^2=4a^2[/tex]
[tex] 4a^{2} =676[/tex]
[tex] a^{2}=169 [/tex]
[tex]a=13[/tex]
P=[tex]4a=4*13=52cm[/tex]