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Stiind ca a-c=37 si ab-bc+13=36b+42, calculați b si a+3b-c. Pls ajutati-mă!

Răspuns :

Inlocuim a-c =37 in ab-bc+13=36b+42 Adica b(a-c)+13=36b+42 37b-36b=42-13 b=29 Iar a+3b-c=a-c+3*29=37+87=124
ab-bc+13=36b+42, b(a-c)+13=36b+42, b*37+13=36b+42,37b-36b=42-13,b=29, a+3b-c=a-c+3b=37+3*29=124