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x(x+3)=(x+1)^2 si 3(x+5)=2(x+8)

Răspuns :

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Vezi imaginea ANDREEAPBA
1)
[tex]x(x+3)=(x+1)^{2} \\ x(x+3)=(x+1)(x+1) \\ x(x+3)=x(x+1)+1(x+1) \\ x(x+3)=x^{2}+1x+1x+1 \\ x(x+3)=x^{2}+2x+1 \\ x(x+3)-(x^2+2x+1)=0 \\ x-1=0 \\ x=0+1 \\ x=1[/tex]
2)
[tex]3(x+5)=2(x+8) \\ 3x+15=2x+16 \\ 3x-2x=16-15 \\ x=1[/tex]
Sper ca te-am ajutat!