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Calculati Sumele 1+2+3+...22

Răspuns :

se foloseste Suma lui Gaus
1+2+3+...+22= 22*23/2
se simplifica 22 cu 2
1+2+3+...+22=11*23= 253

deci 1+2+3+...+22=253
[tex]\displaystyle 1+2+3+...+22= \frac{22(22+1)}{2} = \frac{22 \times 23}{2} = \frac{506}{2} =253[/tex]