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Aflati numerele naturale a b c care verifica simultar egalitatile
a+b=24
b+c=18
c+a= 26
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Răspuns :

a + b = 24
b + c = 18
c + a = 26
2a + 2 b + 2c = 68
2 ( a + b + c ) = 68
a + b + c = 68 : 2
a + b + c = 34
24 + c = 34
c = 34 - 24
c = 10
b + c = 18
b + 10 = 18
b = 18 - 10
b = 8
c + a = 26
10 + a = 26
a = 26 - 10
a = 16
verificam
16 + 8 + 10 = 34