d=m/V => m=d*V=0,88*200=176g benzen
78g.....22,4l.....112,5g
C₆H₆ + Cl₂ -> C₆H₅-Cl + HCl
176g....x=?......y=?
acum, cantitatile teoretice sunt egale cu x si y, insa stim ca doar 705 din masa benzenului se monoclorurareaza => 70% din x se obtine, y va fi in exces
x=176*22,4/78
y=176*112,5/78=50,54l Cl₂ necesari
70/100=mpractica/y
Vpractic=70x/100=70*176*22,4/78*100=35,38l Cl₂ transformat
mpractica=70*y/100=70*176*112,5/78*100=177,69g clorobenzen
Mclorobenzen=72+5+35,5=122,5
%C=72*100/112,5=64% C
%H=5*100/112,5=4,44% H
%Cl=35,5*100/112,5=35,55% Cl
