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5x-7 ≥ -4x+11. Ajutati-ma va rog!

Răspuns :

[tex]\displaystyle 5x-7 \geq -4x+11 \\ 5x+4x \geq 11+7 \\ 9x \geq 18 \\ x \geq \frac{18}{9} \\ x \geq 2 \\ x \in [2, \infty)[/tex]
[tex]5x-7 \geq -4x+11 \\ 5x+4x \geq 11+7 \\ 9x \geq 18 \\ x \geq \frac{18}{9} \\ x \geq 2 \\ [/tex]
x∈[2,∞)