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|x+2|=radical din 5
|2x|=-8
|x+1|=2/5
|x-7/3|=0
imi trebuie urgeeent va roog
cat este x?


Răspuns :

1.x=radical din5 -2
x=-radicald din 5-2
2.modulul nu e cu minus
3.x=7/5
x=3/5
4.x=7/3
[tex]a).|x+2|= \sqrt{5} \\ x+2= \sqrt{5} \\ x= \sqrt{5} -2 \\ x+2=- \sqrt{5} \\ x=- \sqrt{5} -2 \\ b).|2x|=-8 \Rightarrow Nu~are~solutii[/tex]
[tex]\displaystyle c).|x+1|= \frac{2}{5} \\ x+1= \frac{2}{5} \\ 5x+5=2 \\ 5x=2-5 \\ 5x=-3 \\ x=- \frac{3}{5} \\ x+1=- \frac{2}{5} \\ 5x+5=-2 \\ 5x=-2-5 \\ 5x=-7 \\ x=- \frac{7}{5} [/tex]
[tex]\displaystyle d).\left|x- \frac{7}{3} \right|=0 \\ x- \frac{7}{3} =0 \\ 3x-7=0 \\ 3x=0+7 \\ 3x=7 \\ x= \frac{7}{3} [/tex]