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daca a=b=24 si b+c=5 cum se rezolva asta; a+2b+c=?,2a+5b+3c=?,a x c+b xc=???

Răspuns :

 1. a=b=24 si b+c=5 a+2b+c=a+b+b+c=a+b+(b+c)24+24+5=48+5=53 deci
a+2b+c=53

2. 2a+5b+3c=2a+2b+3b+3c=2(a+b)+3(b+c)=2×(24+24)+3×5=96+15=111
deci  2a+5b+3c=111

3. a×c+b×c
b+c=5⇒  c=5-b=5-24⇒b=-19
deci 

a×c+b×c=c(a+b)=-19(24+24)=-19×48=- 912