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x+1\2-3\8=x\3    
care e x Q+    
Vreau si calculele.


Răspuns :


[tex]x+ \frac{1}{2}- \frac{3}{8} = \frac{x}{3} [/tex]
Se aduce la celasi numitor:
[tex]\frac{24*x}{24} + \frac{12}{24}- \frac{3*3}{24} = \frac{8*x}{24}[/tex]
24*x+12-9=8*x
24*x-8*x+3=0
16x=-3
[tex]x=- \frac{3}{16} [/tex]