[tex]\text{Bisectoarea } \widehat{ABC} \text{ intersecteaza latura AB in D. } \\
AM~ ||~ BD ~~~ intersectate~de~secanta~BC \\
\Longrightarrow ~~~ \widehat{DBC} = \widehat{AMC} = 40^o ~~~ (ca ~unghiuri~ corespondente) \\
\widehat{ABC} = 2 \times \widehat{DBC} = 2 \times 40 = 80^o ~~~(Deoarece ~BD ~este~ bisectoare.) \\
\Longrightarrow ~~~ \widehat{ABC} = \widehat{ACB} = 80^o \\
\Longrightarrow ~~~ \Delta ABC ~~\text{este isoscel cu baza BC si }~AB=AC.[/tex]