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Aflati media aritmetica si medai geometrica a nr : a = 4 + [tex] \sqrt{7} [/tex] si b = [tex]4- \sqrt{7} [/tex]

Răspuns :

Ma = [tex] \frac{a+b}{2} = \frac{4+ \sqrt{7}+4-\sqrt{7}}{2} = \frac{8}{2}=4 [/tex]

Mg = [tex] \sqrt{a*b} = \sqrt{(4-\sqrt{7})*(4+ \sqrt{7})}= \sqrt{16-7}= \sqrt{9}=3 [/tex]