[tex]\frac{5}{3}x + \frac{2}{9} + 1\frac{1}{3}[/tex] =
[tex]\frac{5x}{3} + \frac{2}{9} + \frac{4}{3}[/tex] = aducem la acelasi numitor adica 9
[tex]\frac{15x}{9} + \frac{2}{9} + \frac{12}{9} [/tex] scapam de numitor
15x + 2 = 12
15 x= 12-2
15x = 10
x= [tex] \frac{10}{15} = \frac{2}{3} [/tex]