a) A=ABxBC=480 cm³
P=2(AB+BC)=88 cm²
b) AAMB=MNxAB/2=240cm²
PAMB=AM+MB+AB
Δ AMD dreptunghic se aplica t lui Pitagora
AM²=AD²+DM²
DM=DC-MC=18 cm
AM²=400+324⇒AM=2√181
ΔMCB dreptunghic s e aplica t Piagora
MB²=MC²+BC²
MB=2√109
P=2√181+2√109+24 cm
c) AMB=AM+MB=2√181+2√109=2x13.4+2x10.4≈47.68
DAB=DA+AB=20+24=44
primul ajunge cel care parcurge DAB pt ca dist e mai mica