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X2-9x+8 < sau = ca 0???va rig frumos

Răspuns :

[tex]x^2-9x+8 \leq 0 \\ (x-1)(x-8) \leq 0 \\ x-1 \leq 0 \\ x \leq 0+1 \\ x \leq 1 \\ x-8 \leq 0 \\ x \leq 0+8 \\ x \leq 8[/tex]