(x²-2x-15) /(x²-10x+25) =
=(x²-5x+3x-15) /(x-5)² =
=[x(x-5)+3(x-5)] /(x-5)² =
=(x-5)(x+3) /(x-5)² =
=(x+3) /(x-5)
Din dublul unui numar necunoscut se scade 0,(3)diferenta obtinuta se imparte la 1,4(6) se obtine rezultatul0,(45).
x=nr
0,(3)=3/9=1/3
1,4(6)=(146-14)/90=132/90=44/30
0,(45)=45/99 =5/11
(x-1/3 ):44/30= 5/11
(x-1/3 ) × 30/44= 5/11
x-1/3 = 5/11 : 30/44
x-1/3 = 5/11 × 44/30
x-1/3 = 4/6
x-1/3=2/3
x=2/3+1/3
x=3/3
x=1
x=7/9
