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4^5*2^14*x+8^=4^14 . determinal pe x


Răspuns :

[tex] 4^{5}* 2^{14}*x+8^{6}=4^{14} \\ 4^{5}*4^{7}*x+8^{6}=4^{14} \\ 4 ^{5+7}*x+8^{6}=4^{14} \\ 4^{12}x+8^{6}= 4^{14} \\ 4^{12}x= 4^{14}: 8^{6} \\ 4^{12} x=4^{14}:4^{9} \\ 4^{12}x=4^{14-9} \\ 4 ^{12}x= 4^{5} \\ x= 4^{12}: 4^{5} \\ x= 4^{12-5} \\ x=4^{7} [/tex]