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determinati numerele  x,y si z direc proportionale cu numerele 3, 4 si 6 daca z-y+x=10



Răspuns :

{x,y,z} D.P {3,4,6}
[tex] \frac{x}{3}= \frac{y}{4} = \frac{z}{6} => \frac{z-y+x}{6-4+3}= \frac{10}{5} =2[/tex]

[tex] \frac{x}{3}=2 => x=3*2=6 [/tex]
[tex] \frac{y}{4}=2 => y=4*2=8 [/tex]
[tex] \frac{z}{6} =2 => z=6*2=12[/tex]