√2/(√3+2√2)-(√6-4√2)/(2√2 -3) =
=[√2(√3-2√2)/(√3+2√2)(√3-2√2)] -[(√6-4√2)(2√2 +3)/(2√2 -3)(2√2 +3)] =
=[√6-4)/(3-8)] -[(2√12-16+3√6-12√2)/(8-9)] =
=[√6-4)/(-5)] -[(4√3-16+3√6-12√2)/(-1)] =
=(-0,2√6+0,8) +(4√3-16+3√6-12√2) =
=-0,2√6+0,8 +4√3-16+3√6-12√2 =
=2,8√6+4√3-15,2-12√2≈-18,383788238
deci irational