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√28+(1+√ 2)²-√8+(1-√7)²=?

Răspuns :

[tex] \sqrt{28} +(1+ \sqrt{2} )^2- \sqrt{8} +(1- \sqrt{7} )^2= \\ =2 \sqrt{7} +1^2+2 \cdot 1 \cdot \sqrt{2} + \sqrt{2} ^2-2 \sqrt{2} +1^2-2 \cdot 1 \cdot \sqrt{7} + \sqrt{7} ^2= \\ =2 \sqrt{7} +1+2 \sqrt{2} +2-2 \sqrt{2} +1-2 \sqrt{7} +7=11[/tex]