👤

Calculați
A= 3√32 - 4√27 - 5√72 + 6√108
B= 2√243 + 5√50 - 2√75 -11√8
C= √48 -√108 + √192 - √243 + √75
D=√96 - √294 + √24 - √54 + √150


Răspuns :

[tex]a=3 \sqrt{32} -4 \sqrt{27} -5 \sqrt{72} +6 \sqrt{108} \\ a=12 \sqrt{2} -12 \sqrt{3} -30 \sqrt{2} +36 \sqrt{3} \\ a=-18 \sqrt{2} +24 \sqrt{3} \\ b=2 \sqrt{243} +5 \sqrt{50} -2 \sqrt{75} -11 \sqrt{8} \\ b=18 \sqrt{3} +25 \sqrt{2} -10 \sqrt{3} -22 \sqrt{2} \\ b=8 \sqrt{3} +3 \sqrt{2} [/tex]
[tex]c= \sqrt{48} - \sqrt{108} + \sqrt{192} - \sqrt{243} + \sqrt{75} \\ c=4 \sqrt{3} -6 \sqrt{3} +8 \sqrt{3} -9 \sqrt{3} +5 \sqrt{3} \\ c=2 \sqrt{3} \\ d= \sqrt{96} - \sqrt{294} + \sqrt{24} - \sqrt{54} + \sqrt{150} \\ d=4 \sqrt{6} -7 \sqrt{6} +2 \sqrt{6} -3 \sqrt{6} +5 \sqrt{6} \\ d= \sqrt{6} [/tex]