1.a) 35a div cu 2 =>a={0,2,4,6,8}, nr sunt: 350,352,354,356,358.
b)3ab div 3 => (a=0, b=0);(a=3,b=3); (a=4,b=2); (a=2,b=4); (a=1,b=5); (a=5, b=1)
nr sunt: 300, 333,342,324,315,351
2. 7\12 ----- 5\18
21\36------10\36
21\36>10\36=>7\12>5\18
3.x={1,-1,3,-3,9,-9}