[tex]\displaystyle a).3 \sqrt{2} x+7=0 \\ 3 \sqrt{2} x=0-7 \\ 3 \sqrt{2} x=-7 \\ x=- \frac{7}{3 \sqrt{2} } \Rightarrow x=- \frac{7 \sqrt{2} }{6} [/tex]
[tex]\displaystyle b).16x-3(x+1)=5x \\ 16x-3x-3=5x \\ 16x-3x-5x=3 \\ 8x=3 \\ x= \frac{3}{8} [/tex]
[tex]\displaystyle c).2,5(x-4)-6x=3-x \\ 2,5x-10-6x=3-x \\ 2,5x-6x+x=3+10 \\ -2,5x=13 \\ x=- \frac{13}{2,5} \\ x=-5,2[/tex]
[tex]\displaystyle d).x^2-3x-10=0 \\ a=1,b=-3,c=-10 \\ \Delta=b^2-4ac=3^2-4 \cdot 1 \cdot (-10)=9+40=49\ \textgreater \ 0 \\ x_1= \frac{3+ \sqrt{49} }{2 \cdot 1} = \frac{3+7}{2} = \frac{10}{2} =5 \\ \\ x_2= \frac{3- \sqrt{49} }{2 \cdot 1} = \frac{3-7}{2} = \frac{-4}{2} =-2[/tex]
[tex]\displaystyle e).2x^2+7x-8=0 \\ a=2,b=7,c=-8 \\ \Delta=b^2-4ac=7^2-4 \cdot2 \cdot (-8)=49+64=113\ \textgreater \ 0 \\ x_1= \frac{-7+ \sqrt{113} }{2 \cdot 2} = \frac{-7+ \sqrt{113} }{4} \\ \\ x_2= \frac{-7- \sqrt{113} }{2 \cdot 2} = \frac{-7- \sqrt{113} }{4} [/tex]
[tex]\displaystyle f).-x^2+10x+2=0 \\ a=-1,b=10,c=2 \\ \Delta=b^2-4ac=10^2-4 \cdot (-1) \cdot 2=100+8=108\ \textgreater \ 0 \\ x_1= \frac{-10+ \sqrt{108} }{2 \cdot (-1)} = \frac{-10+6 \sqrt{3} }{-2} = \frac{-2(5-3 \sqrt{3} )}{-2} =5-3 \sqrt{3} \\ \\ x_2= \frac{-10- \sqrt{108} }{2 \cdot (-1)} = \frac{-10-6 \sqrt{3} }{-2} = \frac{-2(5+3 \sqrt{3} )}{-2} =5+3 \sqrt{3} [/tex]
