3x=12y=11z=t am egalat tot sirul cu un numar natural t sa ne fie mai usor, iar acum 3x=t⇒x=[tex] \frac{t}{3} [/tex]
12y=t⇒y=[tex] \frac{t}{12} [/tex]
11z=t⇒z=[tex] \frac{t}{11} [/tex]
2x+3y=56
[tex]2\cdot \frac{t}{3}+3\cdot \frac{t}{12}=56 \\ ^4/\frac{2t}{3}+ \frac{3t}{12}=56 \\ \frac{8t+3t}{12}=56 \\ \frac{11t}{12}=56 \\ t=56: \frac{11}{12} \\ t=56\cdot \frac{12}{11} \\ t= \frac{672}{11}[/tex]
si stim ca x=[tex] \frac{t}{3} [/tex] deci x=[tex] \frac{672}{11}\cdot \frac{1}{3}[/tex] deci x=[tex] \frac{224}{11} [/tex]
y=[tex] \frac{672}{11}\cdot \frac{1}{12} [/tex]
y=[tex] \frac{56}{11} [/tex]
z=[tex] \frac{672}{11}\cdot \frac{1}{11} [/tex]
z=[tex] \frac{672}{121} [/tex] si am aflat numerele: x=[tex] \frac{224}{11} [/tex] ,y=[tex] \frac{56}{11} [/tex] iar z=[tex] \frac{672}{121} [/tex]
