Notam cu N numarul dat
[tex]|\sqrt5(6-8.15)|=|\sqrt5||6-8.15|=\sqrt5(8.15-6)=\sqrt5\cdot2.15=\sqrt5\cdot1.5^2\\
|(\sqrt3-\sqrt5)^2|=(\sqrt3-\sqrt5)^2 =3-2\sqrt{15}+5=8-2\sqrt15\\
|\frac{1-\sqrt5}{5-6.5}|=\frac{\sqrt5-1}{6.5-5}=\frac{\sqrt5-1}{1.5}=\frac{2}{3}\sqrt5-\frac{2}{3}\\
N=1.5^2\sqrt5+8-2\sqrt{15}-\frac{2}{3}\sqrt5
+\frac{2}{3}=\sqrt5(\frac{225}{100}-\frac{2}{3})-2\sqrt{15}+8+\frac{2}{3}=\\
=\boxed{\frac{19}{12}\sqrt5-2\sqrt{15}+\frac{36}{3}}
[/tex]
