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Am nevoie de un raspuns la x² -3x + 2 = 0 repede va rog

Răspuns :

[tex]\displaystyle x^2-3x+2=0 \\ a=1,b=-3,c=2 \\ \Delta=b^2-4ac=3^2-4 \cdot 1 \cdot 2=9-8=1\ \textgreater \ 0 \\ x_1= \frac{3+1}{2}= \frac{4}{2} =2 \\ \\ x_1= \frac{3-1}{2} = \frac{2}{2} =1[/tex]
a=1
b=-3
c=2
Δ= b²-4ac =3²-4*2=9-8=1
x1=( -b+√Δ)/2a=(3+1)/2=4/2=2
x2=( -b-√Δ)/2a=(3-1)/2=2/2=1