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3,(2)+x mai mic decat 9, (7) in N

Răspuns :

[tex]\displaystyle 3,(2)+x\ \textless \ 9,(7) \\ \frac{29}{9} +x\ \textless \ \frac{88}{9} \\ x\ \textless \ \frac{88}{9} - \frac{29}{9} \\ x\ \textless \ \frac{59}{9} \\ x\ \textless \ 6,(5) \\ x \in \{0;1;2;3;4;5;6\}[/tex]