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sa se determine ratia si suma primilor 15 termini intr-o progresie aritmetica daca a3=12 si a4=16


Răspuns :

r=a4-a3=16-12=4
a3=a1+2*r
a1=a3-2*r
a1=12-8=4
[tex]S_{15}= \frac{ (a_{1}+ a_{15})*15 }{2} [/tex]
a15=a1+14*r=4+14*4=4+56=60
[tex] S_{15}= \frac{(4+60)*15}{2}= \frac{64*15}{2}=480[/tex]0