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Media aritmetică a 3 numere naturale consecutive este 25. Aflati numele

Răspuns :

(a+b+c):3 = 25 | * 3
a+b+c= 75
b= a+1
c=a+2
 Inlocuim : a+a+1+a+2 = 75
3a+3=75 | - 3
3a = 72
a= 72:3
a=24
b=24+1=25
c=24+2=26



Ma(media aritmetica)=x+x+1+x+2/3=25

x+x+1+x+2=25*3=75

Nr.sunt:

I.x ,

II.x+1

III.x+2

x+x+1+x+2=75

3x+3=75

3x=75-3=72

3x=72

x=72/3=24

I.24

II.25

III.26