A
B D M C
daca AM = 25 in Δ ABC drept ⇒ BC = 2·AM = 50 cm
Δ ADM drept AM² = AD² + DM² ; 25² = 24² + DM² ; DM²=625 - 576 =49
DM =√49 = 7 cm
BD = 25 - 7 =18
AB² = BD² + AD² ; AB² = 18² + 24² =900 ; AB = √900 = 30cm
AC² = AD² + DC² = 24² + (7 + 25)² = 1600 AC = √1600 = 40
perim. = 30 cm + 40cm + 50cm = 120 cm
sin MAC = 24 / 40 = 3 / 5