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Calculati compozitia procentuala de masa a glucozei.

Răspuns :

MC6H12O6=12*6+12+16*6=180

Daca la 160gC6H1206..............72gC.........12gH..........96gO
Dar la 100..............................a........................b..........c

a=45%
b=7,5%
c=60%