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Calculati:
a) √3+2√3+7√3-5√3=
b)-3√2+√2-4√2+10√2=
c)4√5+(6√5-7√5)=
d)-(3√6+√6)+11√6=


Răspuns :

[tex]a). \sqrt{3} +2 \sqrt{3} +7 \sqrt{3} -5 \sqrt{3} =3 \sqrt{3} +7 \sqrt{3} -5 \sqrt{3} =10 \sqrt{3} -5 \sqrt{3} =5 \sqrt{3} \\ \\ b).-3 \sqrt{2} + \sqrt{2} -4 \sqrt{2} +10 \sqrt{2} =-2 \sqrt{2} -4 \sqrt{2} +10 \sqrt{2} = \\ \\ =-6 \sqrt{2} +10 \sqrt{2} =4 \sqrt{2} \\ \\ c).4 \sqrt{5} +(6 \sqrt{5} -7 \sqrt{5} )=4 \sqrt{5} - \sqrt{5} =3 \sqrt{5} \\ \\ d).-(3 \sqrt{6} + \sqrt{6} )+11 \sqrt{6} =-4 \sqrt{6} +11 \sqrt{6} =7 \sqrt{6} [/tex]
a) √3+2√3+7√3-5√3=√3×(1+2+7-5)=5√3
b)  -3√2+√2-4√2+10√2=√2×(-3+1-4+10)=4√2
c)  4√5+(6√5-7√5)=√5×(4+6-7)=3√5
d)  -(3√6+√6)+11√6= √6×(-3-1+11)=7√6