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6(2x+3)+4(x-2)<3(3x-2)+37
mersiii


Răspuns :

6(2x+3)+4(x-2)<3(3x-2)+37
12x+18+4x-8<9x-6+37
16x+10<9x+31
16x-9x<31-10
7x<21
x<21/7
x<3
x∈(-∞,+3)