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Cat face (x+2)(x-2)+4(x+3)=(x+2)²-3x va rog ajutatima

Răspuns :

[tex](x+2)(x-2)+4(x+3)=(x+2)^2-3x \\ x^2-4+4x+12=x^2+2*x*2+2^2-3x \\ x^2-4+4x+12=x^2+4x+4-3x \\ x^2-x^2+4x-4x+3x=4+4-12 \\ 3x=-4 \\ x=- \frac{4}{3} [/tex]
x² - 2x + 2x - 4 + 4x + 12 = x² + 4x + 4 - 3x
4x - 4x + 3x = 4 + 4 - 12
3x = - 4
x = - 4/3