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Sa se arate ca [tex] \frac{ \sqrt{6}sin135 }{cos150} [/tex] ∈ Z.
sin135grade si cos150grade


Răspuns :

[tex]\frac{ \sqrt{6}sin135 }{cos150} = \frac{ \sqrt{6} * \frac{1}{ \sqrt{2} } }{- \frac{ \sqrt{3} }{2} } = \frac{ \frac{ \sqrt{6} }{ \sqrt{2} } }{- \frac{ \sqrt{3} }{2} } = \frac{ \sqrt{3} }{- \frac{ \sqrt{3} }{2} } =-2[/tex]