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Ofer 99 puncte! Rezolvati : ( radical 2 -radical 2005 ) • ( radical 2 -1 ) / radical 2 -2 = ?

Răspuns :

[tex]\frac{(\sqrt2-\sqrt{2^{2005}})\cdot(\sqrt2-1)}{\sqrt2-2}=\frac{(\sqrt2-\sqrt{2^{2005}})\cdot(\sqrt2-1)}{-\sqrt2(\sqrt2-1)}=\frac{\sqrt2-\sqrt{2^{2005}}}{-\sqrt2}=\frac{\sqrt{2^{2005}}-\sqrt2}{\sqrt2}\\= \frac{\sqrt2(\sqrt{2^{2004}}-1)}{\sqrt2}=\sqrt{2^{2004}}-1=2^{1002}-1[/tex]