1. dupa regula , a=nq+1
b=n(q+1)+2=nq+n+2
c=n(q+2)+3=nq+2n+3
d+n(q+3)+4=nq+3n+4
a+b+c+d=nq+1+ nq+n+2 +nq+2n+3 +nq+3n+4=450
4nq+6n+10=450
2nq+3n=22o n(2q+3)=220
descompunem pe 220 in factori primi
a=44*1+1=45
b=44*2+2=90
c=44*3+3=135
d=44*4+4=180
2.Ai in poza rezolvarea