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Suma a doua nr naturale este119.Daca le impartimobtinem catul 3 si restul 19. aflati cele doua nr

Răspuns :

a+b=119;
⇒a=3b+19;
⇒3b+19+b=119
⇒4b=100⇒b=25;
⇒a=3·25+19
⇒a=75+19⇒a=94;
[tex]a+b=119 \\ a:b=3r19=\ \textgreater \ a=3b+19 \\ 3b+19+b=119 \\ 4b=119-19 \\ b=100:4 \\ b=25 \\ a=3*25+19 \\ a=94[/tex]