[tex] \sqrt[3]{x^2-x-3}=-1 \\ \\ Ridicam~la~cub~si~obtinem: \\ \\ x^2-x-3=-1 \\ \\ x^2-x-2=0 \\ \\ \Delta=(-1)^2-4 \cdot 1 \cdot (-2)=9 \\ \\ x_{1,2}= \frac{1 \pm \sqrt { \Delta}}{2}= \frac{1 \pm 3}{2} = \left \{ {{-1} \atop {2}} \right. . \\ \\ \underline{Solutie}: x \in \{-1;2\}. [/tex]
[tex]*Ecuatia~x^2-x-2=0~se~putea~rezolva~mai~rapid~astfel: \\ \\ x^2-x-2=0 \Leftrightarrow (x+1)(x-2)=0 \Rightarrow x \in \{-1;2\}.[/tex]
