I_______________________I______________________I___________________________I
a b c
a,b,c cele trei nr
a+b+c=1010
126+381+260=767
1010-767=243
243/3=81
nr care se scade consecutiv din a,b,c
a-81=1`26=>a=126+81=>a=207
b-81=381=>b=381+81=>b=462
c-81=260=>c=260+81=>c=341
verificare
207+462+341=1010