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determinati nr prime a si b stiind ca 3a+16b=54


Răspuns :

[tex]3a+16b=54 \\ 3a=54-16b \\ 3a=2(27-8b) \\ (3,2)=1 \Rightarrow 2 | a \Rightarrow a=2. \\ \\ 3a+16b+54 \Leftrightarrow 3 \cdot 2 +16b=54 \Leftrightarrow6+16b=54 \Leftrightarrow 16b=48 \Rightarrow b=3. \\ \\ Solutie:~a=2~si~b =3.[/tex]