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(1/√2+1)totul*2+(1\√2-1)totul*2- 1\2=?

Răspuns :

[tex]\frac{1}{\sqrt2+1}2+\frac{1}{\sqrt2-1}2-\frac{1}{2}=2[\frac{(\sqrt2-1)}{(\sqrt2+1)(\sqrt2-1)}+\frac{(\sqrt2+1)}{(\sqrt2+1)(\sqrt2-1)}]-\frac{1}{2}=\\ 2[\frac{\sqrt2-1}{1}+\frac{\sqrt2+1}{1}]-\frac{1}{2}=4\sqrt2-\frac{1}{2} [/tex]