👤

Determinati termenul necunoscut din egalitatea [(a+260:2)x3+6]x3=2007

Răspuns :

[(a+260:2)x3+6]x3=2007
(a+130)x3+6=2007:3
(a+130)x3=669-6
(a+130)x3=663
a+130=663:3
a+130=221
a=91
[(a+130)x3+6]x3=2007
(3a+390+6)x3=2007
(3a+396)x3=2007
9a+1188=2007
9a=2007-1188
9a=819
a=819:9
a=91