amplificati raportul alegebric x+3/2x-1cu2x+1
x+v7/x-v7cux+v7
simplificati raportul algebricpina la un raport ireductibil
3x+9/x2y+6x+9
efectuati
5/x-2y-3/x+2y


Răspuns :

[tex] \frac{(2x+1)(x+3)}{(2x-1)(2x+1)} = \frac{2 x^{2} +7x+3}{4 x^{2}+2x-2x-1 } = \frac{2x^{2}+7x+3 }{4 x^{2}-1 } [/tex]
[tex] \frac{(x+7y)(x-7y)}{(x-7y)(x+7y)} = \frac{ x^{2}+7xy-7xy-49 y^{2} }{ x^{2} +7xy-7xy-49 y^{2} } = \frac{ x^{2}+49 y^{2} }{ x^{2}+49 y^{2} } =1[/tex]