descompuneti in factori :     ( [tex] x^{2} [/tex] + 2x - 8 ) * ( [tex] x^{2} [/tex] - 4x +4 )
va rog ajutati-ma repede !


Răspuns :

[tex]x^2+2x-8=x^2+2x+1-9=(x+1)^2-3^2=\\ =(x+1-3)(x+1+3)=(x-2)(x+4)\\ x^2-4x+4=(x-2)^2\\ (x^2+2x-8)\cdot(x^2-4x+4)=(x-2)(x+4)(x-2)^2=(x-2)^3(x+4)[/tex]