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(a:2) + (a:4)=141 
si inca unul..
(ax2)+(a:2)=505


Răspuns :

     
[tex](a:2) + (a:4)=141 \\ \\ \frac{a}{2} + \frac{a}{4}=141 \\ \\ \frac{2a}{4} + \frac{a}{4}=141 \\ \\ \frac{2a+a}{4} =141 \\ \\\frac{3a}{4} =141 \\ \\ 3a=141*4 \\ a= \frac{141*4}{3} =47*4=188[/tex]
   
     
[tex](ax2)+(a:2)=505 \\ 2a+ \frac{a}{2}=505 \\ \frac{4a}{2}+ \frac{a}{2}=505 \\ \frac{4a+a}{2}=505 \\ \frac{5a}{2}=505 \\ 5a=505*2 \\ a= \frac{505*2}{5}=101*2=202 [/tex]