4X²-12x+12>0
X∈R
ajutoor


Răspuns :

4x²-12x+12=(4x²-12x+9)+3=(2x-3)²+3.
(2x-3)² ≥0 => 4x²-12x+12≥0+3=3, adica 4x²-12x+12>0, oricare ar fi x∈R.