determina pe a din egalitatea 2x1+4x5+3x2+5x3+axa=4x2+7x5+2x2


Răspuns :

2x1+4x5+3x2+5x3+axa=4x2+7x5+2x2
2+20+6+15+axa=8+35+4

43+a²=47
a²=47-43
a²=4
a=2
2x1+4x5+3x2+5x3+axa=4x2+7x5+2x2
2+20+6+15+axa=8+35+2x2
43+axa=43+2x2
axa=2x2⇒ a=2